RRB NTPC CBT I 28 Dec 2020 Shift 2 Paper

© examsiri.com

Question : 60 of 100

Marks: +1, -0

ABCD is a parallelogram. Side BC is produced to E such that BC = CE. Join AE which intersects side CD at P. The area of triangle ABE is:

less than the area of parallelogram ABCD
= to 1/2 of the area of parallelogram ABCD
= to 1/3 of the area of parallelogram ABCD
= to the area of parallelogram ABCD

Go to Question:

Prev Question

Next Question