If \sqrt{19−x{\sqrt{12}}}/{1} = \sqrt{4}−\sqrt{3} then the value of x is equal to:

RRB NTPC CBT I 28 Dec 2020 Shift 2 Paper

Question : 34 of 100

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\;{√{19−x{√{12}}}}/{1} = {√{4}}−{√{3}}

then the value of x is equal to:

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