RRB NTPC CBT I 18 Jan 2021 Shift 1 Paper

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Question : 79 of 100

Marks: +1, -0

Find the value of sin 15°.

$\;{{√{3}}-1}/{{√{2}}}$
$\;{√{3}+1}/{{√{ }} \ov{2}}$
$\;{{√{3}}+1}/{2 {√{2}}}$
$\;{{√{3}}-1}/{2 {√{2}}}$

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