RRB NTPC CBT I 10 Jan 2021 Shift 2 Paper

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Question : 76 of 100

Marks: +1, -0

(1 -

\;{1}/{n}

) + (1 -

\;{2}/{n}

) + (1 -

\;{3}/{n}

) + up to n term will result as:

$\;{1}/{2n}$
$\;{n−1}/{2}$
$\;{1}/{n^{2}}$
$\;{1}/{2n−1}$

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