The value of \frac{12−[(3−5) \times 4] \div 8−8 + [6 \div (12 \times 2)]}{9 \times 15 \div (12 \times 10)−[12 \div (6 \times 2)]} is:

RRB NTPC CBT 2 Level 4 Exam 10 May 2022 Shift 1

Question : 62 of 120

Marks: +1, -0

The value of

\;{12−[(3−5)\;×\;4]\;÷\;8−8\;+\;[6\;÷\;(12\;×\;2)]}/{9\;×\;15\;÷\;(12\;×\;10)−[12\;÷\;(6\;×\;2)]}

is:

Go to Question:

Prev Question

Next Question