RRB NTPC 29 April 2016 Paper

Question : 57 of 100

Marks: +1, -0

If 40

x^2

734^2

−

234^2

, then find the value of x.

Solution:

(1)

40 x ^ { 2 } = 734 ^ { 2 } - 234 ^ { 2 }

40 x ^ { 2 } = ( 734 - 234 ) ( 734 + 234 )

x ^ { 2 } = { 500 × 968 }/ { 40 }

x ^ { 2 } = 12100

x ^ { 2 } = ( 110 ) ^ { 2 }

x = 110

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