RRB NTPC 29 April 2016 Paper

Question : 41 of 100

Marks: +1, -0

If Rahul walks at 4 km/h, he reaches office late by 10 minutes of the scheduled time. If he walks at 5 km/h, he reaches office 5 minutes ahead of scheduled time. Calculate the distance of his office from his home.

4 km
6 km
5 km
8 km

Validate

Solution:

(3) Let distance be = x
When speed is 4 km/h, time

{T}_{1}

x/4

When speed is 5 km/h, time

{T}_{2}

x/5

Total time difference = 10 – (–5)
i.e., 15 min or

15/60

hours

{ x } /{ 4 } - \ { x } /{ 5 } = { 15 } /{ 60 } ⇒ { x }/ { 20 } = { 15 } /{ 60 }

\⇒ x = 5 { km }

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