RRB NTPC 28 April 2016 Paper

Question : 65 of 100

Marks: +1, -0

Find the HCF of 315, 630 and 945.

Solution:

(1)

315 = \ov { 3 × 3 }×\ov { 5× 7 }

630= \ov {3 × 3} × 2 ×\ov {5 × 7}

945 = \ov {3 × 3} × 3 × \ov {5 × 7}

So, HCF = 315.

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