RRB NTPC 28 April 2016 Paper

Question : 17 of 100

Marks: +1, -0

What is the value of the expression?
(Tan0° Tan1° Tan2° Tan3° Tan4° .....Tan89°)

Solution:

∵ \tan 0 ^ { ° } = 0

∴ ( \tan 0 ^ { °} \tan 1 ^ { ° } .......... . \tan 89 ^ { ° } \ ) =

0 × ( \tan 1 ^ { ° } .......... . \tan 89 ^ { ° } \ )

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