RRB NTPC 18 January 2017 Paper

Question : 48 of 120

Marks: +1, -0

Train P starts from A at 10 am and runs at a constant speed of 60 kmph on a straight line track and reaches B which is at a distance of 360 km. Train Q starts from B at 11 am and run towards A at constant speed. It crosses train P at a distance of 120 km from B. What is the speed of train Q?

40 kmph
30 kmph
50 kmph
60 kmph

Validate

Solution:

(1) Speed of train P = 60 km/hr
Train P will cover distance incrossing train Q = 360 – 120 = 240
Time taken by train Q to cover 240km =

240/60

= 4 hr
T=

D/S

i.e., both the trains will meet at 2p.m. (trains P and Q)
∴ In 3 hr (from 11 a.m. to 2 p.m.),train Q covers 120 km
Speed of train Q =

120/3

= 40km/hr
s=

d/t

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