RRB NTPC 18 January 2017 Paper

Question : 25 of 120

Marks: +1, -0

EIMQUY : CGKOSW : : BFJNRV : ?

Solution:

(4) If then

\table E{––––––––▶}↖{-2}C,B{––––––––▶}↖{-2}Z;I{––––––––▶}↖{-2}G,F{––––––––▶}↖{-2}D;M{––––––––▶}↖{-2}K,J{––––––––▶}↖{-2}H;Q{––––––––▶}↖{-2}O,N{––––––––▶}↖{-2}L;U{––––––––▶}↖{-2}S,R{––––––––▶}↖{-2}P;Y{––––––––▶}↖{-2}W,V{––––––––▶}↖{-2}T

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