RRB Non Technical Model Papers 8 with solutions

Question : 79 of 100

Marks: +1, -0

The value of tan1° tan2° tan3° …………..tan89° is

None of the options
0
-1
1

Solution:

(4)

tan(90° − θ) = cot θtanθ.cot θ=1

(tan θ.cotθ= sinθ /cosθ × cosθ /sinθ=1)

tan89° = tan(90°– 1°) = cot 1°
tan88° = tan(90°– 2°) = cot 2°
∴ Expression (tan1°.tan89°)(tan2°.tan88°) .… .tan45° = (tan1°.cot1°)(tan2°.cot2°) .… .tan45° = 1

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