RRB Non Technical Model Papers 8 with solutions

In Δ ABC and Δ PQR AB = PQ, BC =QR (given) ∠ABD = ∠PQS = 120°∠ABD + ∠ABC = 180°(linear pair)∴ ∠ABC = 60° Similarly, ∠PQR =60° Two sides and their included angle in two triangles is the same,thus by side angle side congruenceΔ ABC ≅ Δ PQR