RRB Non Technical Model Papers 6 with solutions

Question : 61 of 100

Marks: +1, -0

Chords AC and BD of a circle with centre O intersect at right angles at E. If ∠OAB = 25°, then the value of ∠EBC is

30°
25°
20°
15°

Solution:

In triangle OAB, OA = OB = radius,so,
∠AOB = 180° - 2∠OAB = 180° - 50° = 130°
Since angle made by an arc at circumference is half of the angle made at the centre,
$Now, in triangle BEC,

∠EBC =90° -65° = 25°

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