RRB Non Technical Model Papers 10 with solutions

Let (A + C) complete the work in ‘a’days. So B will complete the work in 3 a days.
$1/a+1/{3a}=1/10⇒3a=40⇒a=40/3$
Let (A + B) complete the work in n days. So C will complete the work in 2n days.
$1/n+1/{2n}=1/10⇒n=30/2=15$(A + B + C)'s 1 day's work$ =1/10$
$1/A+1/40+1/30=1/10$
⇒$1/A={12-3-4}/{120}=5/{120}=1/24$Therefore, A will complete the work in 24 days.