RRB Non Technical Model Papers 10 with solutions

Question : 50 of 100

Marks: +1, -0

In the following figure, AB is the diameter of a circle whose centre is O. If ∠AOE = 150°, ∠DAO = 51°, then the measure of ∠CBE is

Solution:

(3) Given, ∠DAO =51°
∠AOE =150°
⇒∠EOB = 180° - 150°= 30°
OE=OB

∠OEB =∠OBE ={150°/2}=75°

NOW,∠CBE= 180°-75° = 105°

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