RRB Junior Engineer Stage 1 Model Papers 9

Question : 6 of 100

Marks: +1, -0

The perimeters of two similar triangle ∆ABC and ∆PQR are 36 cm and 24 cm respectively. If PQ = 10 cm, then AB is:

Solution:

{AB}/{PQ}={BC}/{QR}={CA}/{RP}={AB+BC+CA}/{PQ+QR+RP}

⇒{AB}/{PQ}=36/24

⇒{AB}/10=36/24

⇒AB={36×10}/24=15 cm

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