If x=\frac{4ab}{a+b}, then the value of \frac{x+2a}{x-2a}+\frac{x+2b}{x-2b} is

RRB Junior Engineer Stage 1 Model Papers 9

Question : 23 of 100

Marks: +1, -0

x={4ab}/{a+b}

, then the value of

{x+2a}/{x-2a}+{x+2b}/{x-2b}

Solution:

{x+2a}/{x-2a}+{x+2b}/{x-2b}

Applying compodendo and Dividendo

⇒{x+2a+x-2a}/{x+2a-x+2a}+{x+2b+x-2b}/{x+2b-x+2b}

={2x}/{4a}+{2x}/{4b}⇒x/{2a}+x/{2b}={4ab}/{(a+b)2b}+{4ab}/{(a+b)2b}

={2a}/{a+b}+{2a}/{a+b}×2

Go to Question:

Prev Question

Next Question