RRB Junior Engineer Stage 1 Model Papers 9

Question : 2 of 100

Marks: +1, -0

If ∆ABC is an isosceles triangle with ∠C = 90º and AC = 5 cm, then AB is :

Solution:

∆ABC is an isocoles triangle.
Therefore, AC = BC = 5 cm
Now,

AB^2=AC^2+BC^2

AB^2=5^2+5^2⇒√{25+25}=5√2\cm

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