RRB Junior Engineer Stage 1 Model Papers 8

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Question : 4 of 100

Marks: +1, -0

If

a=b^2/{b-a}

then the value of

a^3+b^3

is

2
6 ab
0
1

Solution:

Given

a=b^2/{b-a}

or

ab-a^2

or

ab=b^2+a^2

We know,

a^3+b^3=(a + b)(a^2+b^2-ob)

∴

(a + b)(ab-ab)⇒0

(using given)

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