RRB Junior Engineer Stage 1 Model Papers 7

Question : 6 of 100

Marks: +1, -0

A batsman in his 12th innings makes a score of 63 runs and there by increases his average scores by 2. What is his average after the 12th innings?

Solution:

Let the average of batsman after 11th innings =A

{\text "Total score at the end of the 11th innings"}/11=A

∴ Total score after 11th innings = 11 A
Now,

{\text "Total score after 11th innings + 12th innings"}/12=A+2

⇒ 11A + 63 = (A + 2) × 12

⇒ 11A – 12 A = 24 – 63

⇒ A = 39

12th innings average

= 39 + 2 = 41

Alternate Method:
He is playing 12th inning increment made in all previous innings
Total increment

= 2 × 11 = 22

runs
His current score = 63
Required average + increment = current score
Required average

= 63 – 22 = 41

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