RRB Junior Engineer Stage 1 Model Papers 7

Question : 27 of 100

Marks: +1, -0

The height of an equilateral triangle is 15 cm. The area of the triangle is

Solution:

AB = BC = CA = 2a cm

AD ⊥ BC

AD=√{AB^2-BD^2}

=√{4a^2-a^2}=√3a ∴√3a=15

⇒a=5√3

∴ Area of triangle

=√3/4×(10√3)^2=75√3

sq.cm.

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