RRB Junior Engineer Stage 1 Model Papers 4

Question : 7 of 99

Marks: +1, -0

What must be added to each term of the ratio 7 : 11, so as to make it equal to 3 : 4 ?

Solution:

Let the required number be x

{7+x}/{11+x}=3/4

⇒ 28 + 4x = 33 + 3x

⇒ x = 33 – 28 = 5

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