RRB Junior Engineer Stage 1 Model Papers 4

Question : 17 of 99

Marks: +1, -0

Two numbers are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The small number is

Solution:

Let two numbers be 3x and 5x

{3x-9}/{5x-9}=12/23

23(3x-9)=12(5x-9)

69x-207=60x-108

9x=99

x=11

Hence, the small number will be

3 ×11 = 33

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