RRB Junior Engineer Stage 1 Model Papers 4

Question : 10 of 99

Marks: +1, -0

The printed price of a book is ₹ 320. A retailer pays ₹244.80 for it. He gets successive discounts of 10% and an another rate. His second rate is :

Solution:

Printed price

= ₹ 320, d_1 = 10%

Let

d_2 = x %

, Amount actually paid = ₹ 244.80
So, amount actually paid

=(1-10/100)(1-x/100)×320

244.80=90/100×{(100-x)}/100×320

100-x={244.80×100×100}/{90×320}=85⇒x=15%

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