RRB Junior Engineer Stage 1 Model Papers 2

Question : 17 of 99

Marks: +1, -0

A jar contains a mixture of two liquids A and B in the ratio 4 : 1. When 10 litre of the mixture is replaced with liquid B, the ratio becomes 2 : 3. The volume of liquid A present in the jar earlier was:

20 lt
10 lt
16 lt
15 lt

Validate

Solution:

Liquid A = 4x litre
Liquid B = x litre
In 10 litres of mixture,
Liquid A

=4/5×10=8 \liter

Liquid B = 2 litre

{4x-8}/{x-2+10}=2/3

⇒ 12x – 24 = 2x + 16

⇒ 10x = 40 ⇒ x = 4

∴ Initial quantity of liquid A = 16 litre

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