RRB Junior Engineer Stage 1 Model Papers 2

Single equivalent discount for successive discounts of 10% and 20%.
$=\left(10+20-\frac{20\times 10}{100}\right)\%=28\%$
Single equivalent discount for 28% and 30% $=\left(28+30-\frac{28\times 30}{100}\right)\%=49.6\%$
Shortcut Method:
Let marked price be 100%
Final discount Here ${\mathit{D}}_1,{\mathit{D}}_2,{\mathit{D}}_3........$ are successive discounts.
Required value