What is the simplified value of \frac{\sin 2A}{1+\cos 2A} ?

Correct Answer is : (1 – cos A) / (1 + cosec A)

RRB Junior Engineer Stage 1 Model Papers 10

Question : 21 of 98

Marks: +1, -0

What is the simplified value of

{\sin 2A}/{1+\cos 2A}

Solution:

(1/{\cosecA+\cot A})^2

⇒1/{(1/{\sinA}+{\cos A}/{\sin A})}={\sin^2 A}/{(1+\cos A)^2}

⇒{1-\cos^2 A}/{(1+\cos A)^2}={(1-\cos A)(1+\cos A)}/{(1+\cos A)^2}

={1-\cos A}/{1+\cos A}

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