If x = 222, y = 223, z = 225 then the value of x^3+y^3+z^3-3xyz is

RRB Junior Engineer Stage 1 Model Papers 10

Question : 15 of 98

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If x = 222, y = 223, z = 225 then the value of

x^3+y^3+z^3-3xyz

Solution:

x^3+y^3+z^3-3xyz=1/2(x+y+z)

[(x-y)^2+(y-z)^2+(z-x)^2]

=1/2(222+223+225)[(222-223)^2+(223-225)^2+(225-222)^2]

⇒1/2[670][1+4+9]=335[14]=4690

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