सरल करें : \cos \\theta(1-\tan \\theta)+\sin \\theta(1-\cot \\theta)

RRB JE Stage I Exam 27 May 2019 Shift 1

Question : 98 of 100

Marks: +1, -0

सरल करें :

\cos \θ(1-\tan \θ)+\sin \θ(1-\cot \θ)

Solution:

\cos \θ(1-\tan \θ)+\sin \θ(1-\cot \θ)

=\cos \θ-\cos \θ\.{\sin \θ}/{\cos \θ}+\sin \θ

-{\cos \θ}/{\sin \θ} \.\sin \θ

=\cos \θ-\sin \θ+\sin \θ-\cos \θ=0

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