RRB JE Stage I Exam 27 May 2019 Shift 1

Question : 72 of 100

Marks: +1, -0

2 x^{2}-15 x+28

के मूल ज्ञात करें।

Solution:

2 x^{2}-15 x+28=0

\⇒2 x^{2}-8 x-7 x+28=0

\⇒2 x(x-4)-7(x-4)=0

\⇒(x-4)(2 x-7)=0

\⇒x=4

या

{7}/{2}

(धनात्मक)

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