RRB JE Stage I Exam 26 May 2019 Shift 1

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Question : 9 of 100

Marks: +1, -0

If tan(A + B) = 0, then –

tan A + tan B = 0
tan A = tan B
$\;{2\tan\;⁡A\:\;+\;\:\tan\;⁡B}/{1\:−\:\tan\;⁡A\tan\;⁡B} = 1$
$\;{2\tan\;⁡A\:\;+\;\:\tan\;⁡B}/{1\:\;+\;\:\tan\;⁡A\tan\;⁡B} = 0$

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