RRB JE Stage I 23 May 2019 Shift 1 (HM)

Question : 60 of 100

Marks: +1, -0

यदि

4 \$ 4 \# 2=8

और

3 \$ 8 \# 2

=12

, है, तो

7 \$ 6 \# 3=?

Solution:

4 \$ 4 \# 2=8

\⇒{4 \×4}/{2}=8

3 \$ 8 \# 2=12

\⇒{3 \×8}/{2}=12

अत:

7 \$ 6 \# 3=?

⇒ ?={7 \×6}/{3}=14

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