सरल कीजिए: \frac{\sin \\theta}{(1-\cos \\theta)}

Correct Answer is : cosecθ+cotθ

RRB JE Stage I 2 Jun 2019 Shift 1 (HM)

Question : 25 of 100

Marks: +1, -0

सरल कीजिए:

{\sin \θ}/{(1-\cos \θ)}

Solution:

{\sin \θ}/{1-\cos \θ}={\sin \θ(1+\cos \θ)}/{(1-\cos \θ)(1+\cos \θ)}

={\sin \θ(1+\cos \θ)}/{1-\cos ^{2} \θ}={\sin \θ(1+\cos \θ)}/{\sin ^{2} \θ}

={1+\cos \θ}/{\sin \θ}={1}/{\sin \θ}+{\cos \θ}/{\sin \θ}

={\cosec} \θ+\cot \θ

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