RRB Group D Model Paper 5 with solutions

(4) According to the rules, when two numbers are multiplied having the same base, their exponents are added. On the other hand, when a number is divided by another number having the same base, the exponent value of the denominator is subtracted from the exponent of the numerator.
So, $4^1\times 4^4÷4^2$ = $4^1\times 4^{\left(4\mathit{–}2\right)}$
= $4^{1+2}$
= $4^3$
Since $4^3=4^{?}$
On comparing, ? = 3