RRB Group D Model Paper 4 with solutions

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Question : 65 of 100

Marks: +1, -0

The minimum value of 2

sin^2

θ + 3

cos^2

θ is

0
3
2
1

Solution:

(2) 2

sin^2

θ + 3

cos^2

θ
= 2

sin^2

θ + 2

cos^2

θ +

cos^2

θ
= 2 +

cos^2

θ
Since the minimum value of cosθ is –1, the minimum value of 2

sin^2

θ + 3

cos^2

θ will be 2 +

(–1)^2

= 2 + 1 = 3.

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