RRB Group D Model Paper 3 with solutions

(2) The ${\mathit{I}}_2$ molecules in iodine are not very soluble in water because they are not opposite in terms of polarity. ${\mathit{I}}_2$ is non-polar whereas ${\mathit{H}}_2\mathit{O}$ is polar. But when KI is added to water containing iodine, it forms a polar compound i.e. K${\mathit{I}}_3$, which is composed of ${\mathrm{K}}^{+}$ and ${\mathit{I}}_3^{-}$ ions. When the compound becomes polar or ionic, it dissolves in polar solvent i.e. water