RRB Group-D Model Paper 19 with answers for online practice

As we see in the figure,
Let, side of the square = a cm.
∴ length of the rectangle = (a + 4) cm.
Breadth of the rectangle = (a – 3) cm.
According to problem,
⇒ ${\mathit{a}}^2$ = (a + 4) (a – 3)
⇒ ${\mathit{a}}^2$ = ${\mathit{a}}^2$ + 4a – 3a – 12
⇒ a =12
∴ length of the rectangle = 12 + 4 = 16 cm.
Breadth of the rectangle = 12 – 3 = 9 cm.
∴ Perimeter of the rectangle = 2 × (16 + 9) = 50 cm.