RRB Group-D Model Paper 18 with answers for online practice

Let the present age of father is x
And the present age of daughter is $\frac{\mathit{x}}{4}$
Therefore, five year hence their age will be:
$\frac{\mathit{x}}{4}+5=\frac{1}{3}\left(\mathit{x}+5\right)$
3x + 60 = 4x + 20
∴ x = 40
So the present age of father is 40, and the present age of daughter is 10.
Now the ratio of their ages after 10 years will be.
$\frac{\left(10+10\right)}{\left(40+10\right)}=\frac{20}{50}$ =2:5
Hence, 2:5 is the correct answer.