RRB Group-D Model Paper 17 with answers for online practice

GIVEN:
(x – 2) is the factor of the polynomial.
CONCEPT:
Here to calculate the remainder we need to substitute value of x in the polynomial that can be calculated putting factor equal to zero.
FORMULAE USED:
Put x = 2 in the polynomial.
CALCULATION:
Remainder = (4 × $2^3$ ) – (2 × $2^2$ ) + (5 × 2) – 8 = 32 – 8 + 10 – 8 = 42 – 16⇒ Remainder = 26
∴ Required remainder is 26