RRB Group-D Model Paper 12 with answers for online practice

Concept used:
Volume of cuboidal box = length × breadth × height
Calculation:
Let breadth of the box be x.
(4x/3) × x × (4x/6) =1536
⇒ $16{\mathit{x}}^3$/18 = 1536
⇒${\mathit{x}}^3$= 1536 × 18/16
⇒${\mathit{x}}^3$ = 1728
⇒ x = 12
length = 4x/3
⇒ 4 × 12/3
⇒ 16
∴ The the length of the box is 16 cm.