RRB Group-D Model Paper 11 with answers for online practice

As per the given data, we know
In one direction Vinod will go by down-stream and return with up-stream and in both cases the distance is same
⇒ Downstream distance = Upstream distance
⇒ (U + 3) 4 = (U – 3)6
⇒ 4U + 12 = 6U – 18
⇒ 30 = 2U
⇒ U = 15 km/hr
∴ Speed of the Vinod in still water = 15 km/hr