RRB Group D Model Paper 10 with solutions

Question : 19 of 100

Marks: +1, -0

If A is an acute angle and cot A + cosec A = 3, then the value of sin A is

Solution:

(2) We know that

cosec^2 \A - cot^2\A

= 1 , so
(cosec A - cot A) =

1/(cosec A+cot A )=1/3

Now, 2cosec A = 3 +

1/3=10/3

cosec A =

5/3

⇒ sinA =

3/5

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