RRB Group D Model Paper 1 with solutions

(3) Let the first angle = 3x°; the second angle = 5x°; third angle = 9x°
The total sum of all the angles of a quadrilateral is 360°.
Now,
3 x + 5 x + 9 x + 71 = 360
x = 17
Therefore,
First angle = 3 × 17 = 51°
Second angle = 5 × 17 = 85°
Third angle = 9 × 17 = 153°
Fourth angle = 71°
The difference between the largest and smallest angles = 153° - 51° = 102°