RRB Group D 3-Oct-2018 Shift 3 Solved Paper

Question : 68 of 100

Marks: +1, -0

A number was divided in the ratio

7: 11 .

When 6 was added to each of the numbers the ratio changed to 5: 7 . The greater of the two initial numbers was :

Solution:

Let the number after division is

7 x

and

11 x

.
Then, from question,

{7 x+6}/{11 x+6}={5}/{7}

49 x+42=55 x+30

6 x=42-30=12

x={12}/{6}=2

Greater number

=11 x=11 ×2=22

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