RRB Group D 3-Dec-2018 Shift 3 Solved Paper

Question : 11 of 100

Marks: +1, -0

A vertical pole, 45 m long, Easts a shadow 15 m long on the ground. At the same time, a vertical building casts a shadow 60 m long on the ground. What is the height of the building?

60m
150m
180m
120m

Validate

Solution:

From Δ ABC, angle of elevation is B
tan θ=

{AB}/{BC}={45}/{15}

tan θ= 3
Now, tan θ=

{\Height \of \the \building}/{\building \show}=3

{\Height \of \the \building}/{60}=3

∴Height of the building= 60×3= 180 m

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