RRB Group D 27-Sep-2018 Shift 1 Solved Paper

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Question : 36 of 100

Marks: +1, -0

When a constant force acts on an object with a mass of

8 \ { kg}

for a duration of

3 \ { s},

it increases the object's velocity from

4 \ { ms}^{-1}

to

6 \ { ms}^{-1}

. What is the magnitude of the applied force?

$5.33 \ { N}$
$4.33 \ { N}$
$6.33 \ { N}$
$3.33 \ { N}$

Solution:

Mass of an object

=8 \ { kg}

\ {V}= {u}+{at}

6=4+3 {a}

2=3 {a}

Acceleration

(a)=2 / 3

{F}={m} ×{a}=8 \×2 / 3

i.e.

16 / 3=5.33 { N}

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