RRB Group D 24-Sep-2018 Shift 1 Solved Paper

Question : 99 of 100

Marks: +1, -0

The length of one side of a rhombus and one of the two diagonals are

16 {cm}

each. The area of the rhombus is _____

Solution:

ATQ, by pythagoras theorem

{CE}^{2}=16^{2}-8^{2}

⇒{CE}^{2}=256-64

{CE}=\√{192}

8 \√{3}

∴

Area of Rhombus

=({1}/{2}×√{192} \×8) \×4

=({1}{2} \× 8 \√{3} ×8) \×4

=128 \√{3}

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