RRB Group D 24-Sep-2018 Shift 1 Solved Paper

Question : 67 of 100

Marks: +1, -0

A person driving at

40 {km} \/ {h}

reaches office 4 minute early while she reaches 5 minutes late if she drivers at

32 {km} \/ {h}

. What is the distance (in

{km}

) that she is covering?

Solution:

ATQ,

40={\text "D"}/{t-{4}/{60}}

.....(1)

32={D}/{t+{5}/{60}}

.....(2)
from eq

(1), D=40(t-{4}/{60})

.......(3)
from eq

(2) D=32(t+{5}/{60})

....(4)

∴ 5 {t}-{20}/{60}=4 {t}-{20}/{60}

⇒{t}={40}/{60}={2}/{3}

Putting the value of

t

in eq (3)

{D}=40({t}-{4}/{60})

=40({2}/{3}-{4}/{60})

{D}=40({40-4}/{60})

={40 \×36}/{60}= 24 \ { km}

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