RRB Group D 24-Sep-2018 Shift 1 Solved Paper

Question : 40 of 100

Marks: +1, -0

The number of iron atoms in a piece of iron weighing

2.8 { g}

is :

Solution:

The number of iron atoms in a piece of iron weighing 2.8 g

56 \ { g}

of iron

=6.022 \× 10^{23}

1g. =6.022×{10^{23}}/{56}

2.8g. =6.022 \× 10^{23} \×2.8 / 56

=3.011 \×10^{22}

atoms

Go to Question:

Prev Question

Next Question